Canonical Minimal Source Completion: The Coarsest Readout Extension on which a Nominated Family of Source Relations Becomes Well Defined
Nested families, refinement maps, and reparameterization
Nested families, refinement maps, and reparameterization
Nested families
Let be sets of indices, the -relations being a subfamily of the -relations (i.e. the relations indexed by are the same functions in both families). Then, directly from (3.5), since agreement of all -relations (and the readout) entails agreement of the sub-collection indexed by (and the readout). In words: a larger nomination is at least as demanding, hence yields an at least as fine completion.
Proposition 7.1 (Canonical refinement maps).
Let . There is a unique map and it is surjective. It satisfies and for every , where the superscripts indicate the completion in which the structure map lives. Moreover , and for ,
Proof. Existence and uniqueness. We exhibit as a relation-sufficient extension for the -family and invoke Theorem 5.1. Indeed, is surjective; satisfies ; and for each the structure map satisfies . Hence is an object of . Theorem 5.1 supplies a unique morphism from it to the terminal object , i.e. a unique map with , and asserts that it is surjective. Compatibility with and with the , , is Lemma 4.3 (equivalently (5.6)).
Identity. For , the identity satisfies ; by the uniqueness just established, .
Cocycle law. Let . Both and are maps . Compose each with the surjection : Two maps out of that agree after precomposition with the surjection agree on all of : given , write and evaluate. Hence (7.3). (Alternatively, both maps are morphisms in , and Theorem 5.1 says there is only one.) ◻
Nested nominations therefore generate a coherent tower of completions, in which each arrow forgets exactly the distinctions that the smaller nomination does not require. This is a hierarchy of information content. Its arrows run from finer to coarser, and by Theorem 5.1 each is uniquely determined by the pair of nominations.
Remark 25 (Strictness is not automatic).
The completion for a larger family is at least as fine as that for a smaller one, and may be strictly finer, but need not be. If every relation indexed by is redundant relative to and the -relations, then by the argument of Corollary 6.3, and is a bijection. Adding relations to the nomination adds information to the completion precisely to the extent that the added relations separate pairs that the existing nomination identifies.
Faithful reparameterization
The completion depends on the distinctions carried by the nominated relations, not on the labels in which their values happen to be recorded. We make this precise.
Proposition 7.3 (Invariance under faithful reparameterization).
For each let be a map whose restriction to the realized subset is injective, and set Let and be the equivalence relations induced by and by (with the same readout ), and let , be the corresponding completions. Then and consequently there is a canonical bijection commuting with the completion maps from and with the projections to :
Proof. . Suppose . Then , and for each , ; applying the function to equal arguments gives . Hence . (Only well-definedness of is used here; injectivity is not.)
. Suppose . Then , and for each , . Both and lie in the realized subset , on which is injective by hypothesis; therefore . As this holds for every , .
This proves (7.6). By Proposition 3.4 applied to each family, , and the composite bijection sends , so it commutes with the completion maps. Since for every , and is surjective, (7.7) follows. ◻
Remark 27 (The precise form of the invariance).
The value spaces and are in general different sets, so and are subsets of different products. Proposition 7.3 therefore asserts an isomorphism of the induced quotients over , equivalently, of the two objects as completions of the readout, and not an identity, nor an isomorphism internal to a single fixed category of relation signatures valued in one fixed product. The relation-signature coordinates are a presentation; the quotient is the invariant. Faithful relabelling of the presentation does not move the invariant.